Answer
$sec^{2}\theta $
Work Step by Step
$\tan ^{2}\theta +1=\dfrac {\sin ^{2}\theta }{\cos ^{2}\theta }+1=\dfrac {\sin ^{2}\theta +\cos ^{2}\theta }{\cos ^{2}\theta }=\dfrac {1}{\cos ^{2}\theta }=sec^{2}\theta $
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.2 Verifying Trigonometric Identities - 7.2 Exercises - Page 666: 6
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