Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.2 Verifying Trigonometric Identities - 7.2 Exercises - Page 666: 17


$1-2\sin \alpha \cos \alpha =1-\sin 2\alpha $

Work Step by Step

$\left( \sin \alpha -\cos \alpha \right) ^{2}=\sin ^{2}\alpha -2\sin \alpha \cos \alpha +\cos ^{2}\alpha =1-2\sin \alpha \cos \alpha =1-\sin 2\alpha $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.