#### Answer

$1$

#### Work Step by Step

$\dfrac {1}{csc^{2}\theta }+\dfrac {1}{sec^2\theta }=\dfrac {1}{\dfrac {1}{\sin ^{2}\theta }}+\dfrac {1}{\dfrac {1}{\cos ^{2}\theta }}=\sin ^{2}\theta +\cos ^{2}\theta =1$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$1$

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