#### Answer

$\csc^2\alpha$

#### Work Step by Step

$\frac{1}{\tan^2\alpha}+\cot\alpha\tan\alpha$
$=(\frac{1}{\tan\alpha})^2+\frac{\cos\alpha}{\sin\alpha}*\frac{\sin\alpha}{\cos\alpha}$
$=\cot^2\alpha+1$
$=\csc^2\alpha$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\csc^2\alpha$

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