#### Answer

$\left( \sin x-\cos x\right) \left( 1+\sin x\cos x\right) $

#### Work Step by Step

$\left( \sin ^{3}x-\cos ^{3}x\right) =\left( \sin x-\cos x\right) \left( \sin ^{2}x+\sin x\cos x+\cos ^{2}x\right) =\left( \sin x-\cos x\right) \left( 1+\sin x\cos x\right) $