Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.2 Verifying Trigonometric Identities - 7.2 Exercises - Page 666: 37


$\tan^2 \beta$

Work Step by Step

$\frac{\sin\beta\tan\beta}{\cos \beta}$ $=\frac{\sin\beta*\frac{\sin\beta}{cos \beta}}{\cos \beta}$ $=\frac{\frac{\sin^2\beta}{\cos\beta}}{\cos \beta}$ $=\frac{\sin^2\beta}{\cos^2\beta}$ $=(\frac{\sin\beta}{\cos \beta})^2$ $=\tan^2 \beta$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.