#### Answer

$\left( 4\tan \beta -3\right) \left( \tan \beta +1\right) $

#### Work Step by Step

$4\tan ^{2}\beta +\tan \beta -3=\left( 4\tan \beta -3\right) \left( \tan \beta +1\right) $

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\left( 4\tan \beta -3\right) \left( \tan \beta +1\right) $

$4\tan ^{2}\beta +\tan \beta -3=\left( 4\tan \beta -3\right) \left( \tan \beta +1\right) $

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.