#### Answer

$\sin^2 x$

#### Work Step by Step

$1-\frac{1}{\sec^2 x}$
$=1-\frac{1}{\frac{1}{\cos^2 x}}$
$=1-\cos^2 x$
$=\sin^2 x$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\sin^2 x$

$1-\frac{1}{\sec^2 x}$
$=1-\frac{1}{\frac{1}{\cos^2 x}}$
$=1-\cos^2 x$
$=\sin^2 x$

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