Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 84


$ x=\pm 2$

Work Step by Step

$\log _{2}\sqrt {2x^{2}}=\dfrac {3}{2}\Rightarrow \sqrt {2x^{2}}=2^{\dfrac {3}{2}}\Rightarrow \left( 2x^{2}\right) ^{\dfrac {1}{2}}=8^{\dfrac {1}{2}}\Rightarrow 2x^{2}=8\Rightarrow$ $ x=\pm 2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.