Answer
$ x=\pm 2$
Work Step by Step
$\log _{2}\sqrt {2x^{2}}=\dfrac {3}{2}\Rightarrow \sqrt {2x^{2}}=2^{\dfrac {3}{2}}\Rightarrow \left( 2x^{2}\right) ^{\dfrac {1}{2}}=8^{\dfrac {1}{2}}\Rightarrow 2x^{2}=8\Rightarrow$
$ x=\pm 2$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 84
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