#### Answer

$-4$

#### Work Step by Step

$\log _{7}\left( x^{3}+65\right) =0\Rightarrow x^{3}+65=7^{0}\Rightarrow x^{3}=\sqrt [3] {7^{0}-65}=\sqrt [3] {1-65}=-4$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$-4$

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