Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises: 50

Answer

$-4$

Work Step by Step

$\log _{7}\left( x^{3}+65\right) =0\Rightarrow x^{3}+65=7^{0}\Rightarrow x^{3}=\sqrt [3] {7^{0}-65}=\sqrt [3] {1-65}=-4$
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