Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises: 70

Answer

$x_{1}=5;x_{2}=-\dfrac {2}{3}$

Work Step by Step

$\log x+\log \left( 3x-13\right) =\log 10\Rightarrow \log \left( x\left( 3x-13\right) \right) =\log 10$ $\Rightarrow x\left( 3x-13\right) =10\Rightarrow 3x^{2}-13x-10=0\Rightarrow \left( x-5\right) \left( 3x+2\right) =0\Rightarrow x_{1}=5;x_{2}=-\dfrac {2}{3}$
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