Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 56


$x_{1}=0,x_{2}=\dfrac {8}{3}$

Work Step by Step

$\log _{5}\left[ \left( 3x+5\right) \left( x+1\right) \right] =1\Rightarrow \left( 3x+5\right) \left( x+1\right) =5^{1}$ $\Rightarrow 3x^{2}+8x+5=5\Rightarrow 3x^{2}+8x=0\Rightarrow 3x^{2}=8x\Rightarrow x_{1}=0,x_{2}=\dfrac {8}{3}$
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