Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 77


$\dfrac {1\pm \sqrt {41}}{4}$

Work Step by Step

$\log _{2}\left( 2x-3\right) +\log _{2}\left( x+1\right) =1\Rightarrow \log _{2}\left( \left( 2x-3\right) \left( x+1\right) \right) =\log _{2}2$ $\Rightarrow \left( 2x-3\right) \left( x+1\right) =2\Rightarrow 2x^{2}-x-3=2\Rightarrow 2x^{2}-x-5=0$ $x_{1,2}=\dfrac {-b\pm \sqrt {b^{2}-4ac}}{2a}=\dfrac {1\pm \sqrt {1-4\times 2\times \left( -5\right) }}{2\times 2}=\dfrac {1\pm \sqrt {41}}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.