Answer
$\{ \frac{9}{2}\}$
Work Step by Step
$log_2(5x-6)-log_2(x+1)=log_23 \longrightarrow log_2(5x-6)=log_23+log_2(x+1) \longrightarrow log_2(5x-6)=log_2(3x+3) \longrightarrow 5x-6=3x+3 \longrightarrow x=\frac{9}{2}$
or $\{ \frac{9}{2}\}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 66
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