Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 55

Answer

$x_{1,2}=0,-8$

Work Step by Step

$\log _{2}\left( \left( 2x+8\right) \left( x+4\right) \right) =5\Rightarrow \left( 2x+8\right) \left( x+4\right) =2^{5}=32$ $\Rightarrow 2\left( x+4\right) ^{2}=32\Rightarrow \left( x+4\right) =\pm \sqrt {16}=\pm 4\Rightarrow x_{1,2}=0,-8$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.