Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises: 62

Answer

$2$

Work Step by Step

$\log \left( x^{2}-9\right) -\log \left( x-3\right) =\log 5$ $\Rightarrow \log \dfrac {\left( x^{2}-9\right) }{\left( x-3\right) }=\log 5\Rightarrow \log \left[ \dfrac {\left( x-3\right) \left( x+3\right) }{x-3}\right] =\log 5$ $\Rightarrow \log \left( x+3\right) =\log 5\Rightarrow x+3=5\Rightarrow x=2$
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