Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 996: 24

Answer

$${\text{ circle}}$$

Work Step by Step

$$\eqalign{ & {x^2} = 25 - {y^2} \cr & {\text{Add }}{y^2}{\text{ to both sides of equation}} \cr & {x^2} + {y^2} = 25 \cr & or \cr & {x^2} + {y^2} = {\left( 5 \right)^2} \cr & {\text{The equation is written in the form }}{\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2} \cr & {\text{Therefore,}} \cr & {\text{The graph of the equation }}{x^2} = 25 - {y^2}{\text{ is a circle}} \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.