Answer
The equation:
$$\frac{(x+2)^2}{9}+\frac{(y-4)^2}{16}=1$$
Represents an ellipse with center (-2,4) and $y$ as the major axis.
Work Step by Step
The equation:
$$\frac{(x+2)^2}{9}+\frac{(y-4)^2}{16}=1$$
Has the form $$\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1$$ where the center of the ellipse is $(h,k)$, and the $a$ represents the major axis. Then the center is $(-2,4)$ and $y$ is the major axis.
