Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 996: 10

Answer

The equation: $(x-2)^2+(y+3)^2=25$ Represents a circle of radius 5 and center (2,-3)

Work Step by Step

The equation: $(x-2)^2+(y+3)^2=25$ Has the form ($x – h)^2 + (y – k)^2 = r^2$ which represents a circle of radius $r$ and center $(h,k)$ We can find the radius by making: $r^2=25$ $r=\sqrt{25}$ $r=5$ And the vertex will be the $(2,-3)$ the terms next to $x$ and $y$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.