Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 996: 20

Parabola ; The equation is a parabola that opens upward with vertex at $(-3, -7)$.

The equation: $y+7=4 (x+3)^2$ Has the form $(y-k)=a(x – h)^2$ which represents a parabola of centre $(h,k)=(-3,-7)$ and $a=4$ Since, the equation $y+7=4 (x+3)^2$ has x-term is squared but y-term is not squared. Thus, the equation is a parabola that opens upward with vertex at $(-3, -7)$.