Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 996: 11

Answer

$${\text{parabola}}$$

Work Step by Step

$$\eqalign{ & y = 2{x^2} + 3x - 4 \cr & {\text{Add 4 to both sides}} \cr & y + 4 = 2{x^2} + 3x \cr & {\text{Complete the square and factor}} \cr & y + 4 - \frac{9}{2} = 2\left( {{x^2} + \frac{3}{2}x + \frac{9}{4}} \right) - \frac{9}{2} \cr & y - \frac{1}{2} = 2{\left( {x + \frac{3}{2}} \right)^2} - \frac{9}{2} \cr & y + 4 = 2{\left( {x + \frac{3}{2}} \right)^2} \cr & {\left( {x + \frac{3}{2}} \right)^2} = \frac{1}{2}\left( {y + 4} \right) \cr & {\text{The equation is written in the form }}{\left( {x - h} \right)^2} = 4p\left( {y - k} \right) \cr & {\text{Therefore,}} \cr & {\text{The graph of the equation }}y = 2{x^2} + 3x - 4{\text{ is a parabola}} \cr} $$
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