Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 996: 13

Answer

$${\text{ parabola}}$$

Work Step by Step

$$\eqalign{ & x - 1 = - 3{\left( {y - 4} \right)^2} \cr & {\text{Divide both sides by }} - 3 \cr & - \frac{1}{3}\left( {x - 1} \right) = {\left( {y - 4} \right)^2} \cr & or \cr & {\left( {y - 4} \right)^2} = - \frac{1}{3}\left( {x - 1} \right) \cr & {\text{The equation is written in the form }}{\left( {y - k} \right)^2} = 4p\left( {x - h} \right) \cr & {\text{Therefore,}} \cr & {\text{The graph of the equation }}x - 1 = - 3{\left( {y - 4} \right)^2}{\text{ is a parabola}} \cr} $$
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