Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 996: 17

Answer

The equation: $$\frac{x^2}{4}-\frac{y^2}{16}=1$$ Represents a hyperbola.

Work Step by Step

The equation: $$\frac{x^2}{4}-\frac{y^2}{16}=1$$ Has the form $$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$$ which represents a hyperbola.
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