Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point: 7

Answer

$\frac{x^2}{y^3}$

Work Step by Step

We follow the laws of exponents to simplify the expression: $$(x^{1/3}y^{-1/2})^6$$$$(x^{1/3})^6(y^{-1/2})^6$$$$x^2y^{-3}$$$$\frac{x^2}{y^3}$$
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