Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point - Page 71: 18



Work Step by Step

$\sqrt[12]{x^{4}}=\quad$ ... for even-indexed roots, the result is an absolute value, $\sqrt[2n]{x^{m}}=|x^{m/2n}|$ $=|x^{\frac{4}{12}}|$ $=|x^{\frac{1}{3}}|$ =$|\sqrt[3]{x}|$
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