## Precalculus (6th Edition) Blitzer

$|\sqrt[3]{x}|$
$\sqrt[12]{x^{4}}=\quad$ ... for even-indexed roots, the result is an absolute value, $\sqrt[2n]{x^{m}}=|x^{m/2n}|$ $=|x^{\frac{4}{12}}|$ $=|x^{\frac{1}{3}}|$ =$|\sqrt[3]{x}|$