Answer
$ x^{6}-4$
Work Step by Step
This is a difference of squares, $(a+b)(a-b)=a^{2}-b^{2}$
... $= (x^{3})^{2}-(2)^{2} \quad$... use the rule: $(a^{m})^{n}=a^{mn}$
=$ x^{6}-4$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Mid-Chapter Check Point - Page 71: 23
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