Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point - Page 71: 23


$ x^{6}-4$

Work Step by Step

This is a difference of squares, $(a+b)(a-b)=a^{2}-b^{2}$ ... $= (x^{3})^{2}-(2)^{2} \quad$... use the rule: $(a^{m})^{n}=a^{mn}$ =$ x^{6}-4$
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