Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point - Page 71: 16


$-\displaystyle \frac{12y^{15}}{x^{3}}$

Work Step by Step

$\displaystyle \frac{24x^{2}y^{13}}{-2x^{5}y^{-2}}=\frac{24}{-2}\cdot\frac{x^{2}}{x^{5}}\cdot\frac{y^{13}}{y^{-2}}\quad$ ... use the rule:$\displaystyle \quad \frac{a^{m}}{a^{n}}=a^{m-n}$ $=-12x^{2-5}y^{13-(-2)}$ $=-12x^{-3}y^{15}\quad $... use the rule: $a^{-n}=\displaystyle \frac{1}{a^{n}}$ =$-\displaystyle \frac{12y^{15}}{x^{3}}$
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