## Precalculus (6th Edition) Blitzer

$-x^{3}$
If $x$ is positive, then $|x|=x$, if $x$ is negative, then $|x|=-x.$ Thus $x^{2}|x|=-x^{2}x^{1}\qquad$... apply $a^{m}a^{n}=a^{m+n}$ =$-x^{3}$