Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point - Page 71: 25

Answer

$10\sqrt{3}$

Work Step by Step

$\sqrt{50}\cdot\sqrt{6}=\sqrt{25\cdot 2}\cdot\sqrt{6} \quad$... use the rule: $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ $=\sqrt{25}\cdot\sqrt{2}\cdot\sqrt{6}\quad$... use the same rule $= 5\sqrt{12} $ $=5\sqrt{4\cdot 3}\quad$... use the same rule $=5\sqrt{4}\cdot\sqrt{3}$ $=5\cdot 2\sqrt{3}$ = $10\sqrt{3}$
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