## Precalculus (6th Edition) Blitzer

$64x^2-48x+9$
We start with the given expression: $(8x-3)^2$ We write this as a product: $(8x-3)(8x-3)$ To use the FOIL method, we multiply the first term from each binomial, the first term from the first binomial and the last term from the second binomial, the last term of the first binomial and the first term of the second binomial, and the last terms of each binomial. We then find the sum of these products and combine the like terms to get our answer. We apply this method to $(8x-3)(8x-3)$:$$(8x-3)(8x-3)=64x^2-24x-24x+9=\\64x^2-48x+9$$