Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 782: 8

Answer

See below:
1571558988

Work Step by Step

The magnitude of the linear combination of the vector is calculated from, $\left\| \mathbf{v} \right\|=\sqrt{{{a}^{2}}+{{b}^{2}}}$ Here, a is the horizontal component of $\mathbf{v}$ and b is the vertical component of $\mathbf{v}$. $\begin{align} & \left\| \mathbf{v} \right\|=\sqrt{{{(-1)}^{2}}+{{(-1)}^{2}}} \\ & =\sqrt{1+1} \\ & =\sqrt{2} \end{align}$ Thus, the magnitude of the vector is $\sqrt{2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.