Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 782: 50



Work Step by Step

Therefore, $\begin{align} & \mathbf{v}=\parallel v\parallel \cos {{330}^{\circ }}\mathbf{i}+\parallel v\parallel \sin {{330}^{\circ }}\mathbf{j} \\ & =\left[ 10\times \left( \frac{\sqrt{3}}{2} \right) \right]\mathbf{i}+\left[ 10\times \left( -\frac{1}{2} \right) \right]\mathbf{j} \\ & =5\sqrt{3}\mathbf{i}-5\mathbf{j} \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.