Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 782: 9

Answer

See below:
1571559023

Work Step by Step

The magnitude of the linear combination of the vector is calculated from, $\left\| \mathbf{v} \right\|=\sqrt{{{a}^{2}}+{{b}^{2}}}$ Here, a is the horizontal component of $\mathbf{v}$ and b is the vertical component of $\mathbf{v}$. $\begin{align} & \left\| \mathbf{v} \right\|=\sqrt{{{(-6)}^{2}}+{{(-2)}^{2}}} \\ & =\sqrt{36+4} \\ & =2\sqrt{10} \end{align}$ Thus, the magnitude of the vector is $\sqrt{40}$.
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