Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 782: 52

Answer

$\mathbf{v}=-0.23\mathbf{i}-0.09\mathbf{j}$

Work Step by Step

Therefore, $\begin{align} & \mathbf{v}=\frac{1}{4}\cos {{200}^{\circ }}\mathbf{i}+\frac{1}{4}\sin {{200}^{\circ }}\mathbf{j} \\ & =\left[ \frac{1}{4}\times \left( -0.9397 \right) \right]\mathbf{i}+\left[ \frac{1}{4}\times \left( -0.3402 \right) \right]\mathbf{j} \\ & =-0.23\mathbf{i}-0.09\mathbf{j} \end{align}$
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