## Precalculus (6th Edition) Blitzer

The values of the components of the vector are $22\sqrt{3}\text{i}+22\text{j}$.
The speed of the football $=44$ feet per second. The angle that the football makes with the horizontal $=30{}^\circ$. The vector component along the x-axis or horizontal is i and the vector component along they-axis or the vertical direction is j. Therefore, the equation becomes \begin{align} & v=\left| \left| v \right| \right|\cos \theta \text{i}\,+\left| \left| v \right| \right|\sin \theta \text{j} \\ & =44\cos 30{}^\circ \text{i}+\,44\sin 30{}^\circ \text{j} \\ & =44\left( \frac{\sqrt{3}}{2} \right)\text{i}+44\left( \frac{1}{2} \right)\text{j} \\ & =22\sqrt{3}\text{i}\,+22\text{j} \end{align}