Answer
The values of the components of the vector are $22\sqrt{3}\text{i}+22\text{j}$.
Work Step by Step
The speed of the football $=44$ feet per second.
The angle that the football makes with the horizontal $=30{}^\circ $.
The vector component along the x-axis or horizontal is i and the vector component along they-axis or the vertical direction is j.
Therefore, the equation becomes
$\begin{align}
& v=\left| \left| v \right| \right|\cos \theta \text{i}\,+\left| \left| v \right| \right|\sin \theta \text{j} \\
& =44\cos 30{}^\circ \text{i}+\,44\sin 30{}^\circ \text{j} \\
& =44\left( \frac{\sqrt{3}}{2} \right)\text{i}+44\left( \frac{1}{2} \right)\text{j} \\
& =22\sqrt{3}\text{i}\,+22\text{j}
\end{align}$
