Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 782: 51



Work Step by Step

Therefore, $\begin{align} & \mathbf{v}=\frac{1}{2}\cos {{113}^{\circ }}\mathbf{i}+\frac{1}{2}\sin {{113}^{\circ }}\mathbf{j} \\ & =\left[ \frac{1}{2}\times \left( -0.39 \right) \right]\mathbf{i}+\left[ \frac{1}{2}\times \left( 0.92 \right) \right]\mathbf{j} \\ & =-0.20\mathbf{i}+0.46\mathbf{j} \end{align}$
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