Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 782: 37

Answer

$\sqrt{10}$

Work Step by Step

Here, $\begin{align} & {{a}_{1}}=2 \\ & {{a}_{2}}=-1 \\ & {{b}_{1}}=-5 \\ & {{b}_{2}}=-6 \end{align}$ Therefore, $\begin{align} & \mathbf{w}-\mathbf{u}=\left[ -1-2 \right]\mathbf{i}+\left[ -6-\left( -5 \right) \right]\mathbf{j} \\ & =-3\mathbf{i}-\mathbf{j} \end{align}$ Therefore, $\begin{align} & \left\| \mathbf{w}-\mathbf{u} \right\|=\sqrt{{{\left( -3 \right)}^{2}}+{{\left( -1 \right)}^{2}}} \\ & =\sqrt{9+1} \\ & =\sqrt{10} \end{align}$
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