Answer
$2-\sqrt 3$
Work Step by Step
Using the half-angle formula $tan\frac{u}{2}=\frac{1-cos(u)}{sin(u)}$, we have $tan\frac{\pi}{12}=\frac{1-cos(\frac{\pi}{6})}{sin(\frac{\pi}{6})}=\frac{1-\sqrt 3/2}{1/2}=2-\sqrt 3$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 5 - Review Exercises - Page 708: 42
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