Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Review Exercises - Page 708: 42


$2-\sqrt 3$

Work Step by Step

Using the half-angle formula $tan\frac{u}{2}=\frac{1-cos(u)}{sin(u)}$, we have $tan\frac{\pi}{12}=\frac{1-cos(\frac{\pi}{6})}{sin(\frac{\pi}{6})}=\frac{1-\sqrt 3/2}{1/2}=2-\sqrt 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.