Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Review Exercises - Page 708: 47

Answer

See explanations.

Work Step by Step

Step 1. Using the Sum-to- Product Formulas, we have $LHS=\frac{2cos(\frac{3x+5x}{2})cos(\frac{3x-5x}{2})}{-2sin(\frac{3x+5x}{2})sin(\frac{3x-5x}{2})}=\frac{cos(4x)cos(x)}{sin(4x)sin(x)}$ Step 2. We have $RHS=cot(x)cot(4x)=\frac{cos(x)}{sin(x)}\times\frac{cos(4x)}{sin(4x)}$ Step 3. Since $LHS=RHS$, we verified the identity.
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