Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Review Exercises - Page 708: 49

Answer

a. $cot(x)$ b. see explanations.

Work Step by Step

a. The graph looks like the function $z=cot(x)$ b. Using the Sum-to- Product Formulas, we have $y=\frac{2cos(\frac{3x+x}{2})cos(\frac{3x-x}{2})}{2cos(\frac{3x+x}{2})sin(\frac{3x-x}{2})}=\frac{cos(2x)cos(x)}{cos(2x)sin(x)}=cot(x)$ Thus functions $y$ and $z$ are equivalent.
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