Answer
$k\pi+\frac{\pi}{6}$
Work Step by Step
Step 1. Given the equation $\sqrt 3tan(x)-1=0$ or $tan(x)=\frac{\sqrt 3}{3}$, we have to find the solutions in $[0,\pi)$ as $x=\frac{\pi}{6}$
Step 2. Consider that the function has a period of $\pi$; we can express the solutions as $x=k\pi+\frac{\pi}{6}$ where $k$ is an integer.
