Answer
$-2sin(x)cos(3x)$
Work Step by Step
Using the Sum-to- Product Formula $sin(u)-sin(v)=2cos\frac{u+v}{2}sin\frac{u-v}{2}$, we have $sin(2x)-sin(4x)=2cos\frac{2x+4x}{2}sin\frac{2x-4x}{2}=2cos(3x)sin(-x)=-2sin(x)cos(3x)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 5 - Review Exercises - Page 708: 45
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