Answer
$x^3+6x^2+12x+8$
Work Step by Step
Binomial Theorem or Binomial expansion can be defined as:
$(x+y)^n=\displaystyle \binom{n}{0}x^ny^0+\displaystyle \binom{n}{1}x^{n-1}y^1+........+\displaystyle \binom{n}{n}x^0y^n$
Need to apply the formula to get the Binomial Expansion.
we have $(x+2)^3=\displaystyle \binom{3}{0}x^32^0+\displaystyle \binom{3}{1}x^{2}2^1+\displaystyle \binom{3}{2}x^12^2+\displaystyle \binom{3}{3}x^02^3$
$=x^3(1)+3(x^2)2+12x+8(1) \bf{(Simplify)}$
$=x^3+6x^2+12x+8$
