Answer
The required solution is ${{\left( 2{{x}^{5}}-1 \right)}^{4}}=16{{x}^{20}}-32{{x}^{15}}+24{{x}^{10}}-8{{x}^{5}}+1$
Work Step by Step
See below:
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1092: 22
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