Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1092: 33



Work Step by Step

Calculate the first three terms of $(x-2y)^{10}$ by using Binomial Theorem or Binomial expansion. This implies $(x-2y)^{10}\\=\displaystyle \binom{10}{0}(x)^{10}(-2y)^0\\+\displaystyle \binom{10}{1}(x)^{9}(-2y)^1+\displaystyle \binom{10}{2})(x)^{8}(-2y)^2$ or, $=x^{10}+10x^9(-2y)+(45)x^8(4y^2)$ or, $=x^{10}-20x^9y+180x^8y^2$
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