Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1092: 31



Work Step by Step

Calculate first three terms for $(x+2)^8$ by using Binomial Theorem. This implies $(x+2)^8=\displaystyle \binom{8}{0}(x)^82^0+\displaystyle \binom{8}{1}(x)^72^1+\displaystyle \binom{8}{2}(x)^62^2$ or, $=x^8+8x^7(2)+(28)x^6(4)$ or, $=x^8+16x^7+112x^6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.