Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1092: 10

Answer

$x^3+12x^2+48x+64$

Work Step by Step

Binomial Theorem or Binomial expansion can be defined as: $(x+y)^n=\displaystyle \binom{n}{0}x^ny^0+\displaystyle \binom{n}{1}x^{n-1}y^1+........+\displaystyle \binom{n}{n}x^0y^n$ Need to apply the formula to get the Binomial Expansion. we have $(x+4)^3=\displaystyle \binom{3}{0}x^34^0+\displaystyle \binom{3}{1}x^{2}4^1+\displaystyle \binom{3}{2}x^14^2+\displaystyle \binom{3}{3}x^04^3$ $=x^3(1)+3(x^2)4+48x+64(1) \bf{(Simplify)}$ $=x^3+12x^2+48x+64$
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