Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1092: 32



Work Step by Step

Calculate the first three terms of $(x+3)^8$ by using Binomial Theorem or Binomial expansion. This implies $(x+3)^8=\displaystyle \binom{8}{0}(x)^83^0+\displaystyle \binom{8}{1}(x)^73^1+\displaystyle \binom{8}{2}(x)^63^2$ or, $=x^8+8x^7(3)+(28)x^6(9)$ or, $=x^8+24x^7+252x^6$
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