Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 8

Answer

$3$

Work Step by Step

By definition: $K=\frac{ab\cdot \sin{(C)}}{2}.$ Hence here $a=4,b=3,C=30^o$ , therefore $K=\frac{4\cdot3\cdot \sin{(30^o)}}{2}=3.$
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