Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 20

Answer

$1.73$ square units

Work Step by Step

By definition: $K=\frac{bc\cdot \sin(A)}{2}.$ Hence, here $K=\frac{4\cdot1\cdot \sin(120^o)}{2}\approx1.73.$
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